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NCERT English Solutions Class 3 to Class 12 Free PDF | Download CBSE English NCERT Solutions

   

English NCERT Solutions PDF Download: Free CBSE NCERT English Solutions are available here for Class 3 to Class 12 students. To help all CBSE Students, we have compiled Class 3 to Class 12 English NCERT Solutions in pdf format on this page. For clearing both board exams and competitive exams, these English solutions are very helpful. So, students can rely on them for better preparation and high scores. Scroll down the page and download NCERT English Textbook Solutions pdf for free within no time.

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NCERT Solutions for Class 10 English Literature Chapter 6 Virtually True

   

NCERT Solutions for Class 10 English Literature Chapter 6 Virtually True are part of NCERT Solutions for Class 10 English. Here we have given NCERT Solutions for Class 10 English Literature Chapter 6 Virtually True.

NCERT Solutions for Class 10 English Literature Chapter 6 provided on this page for free download. Check out NCERT Class X Solutions English Literature Chapter 6 and understand all the concepts easily.

Board CBSE
Textbook NCERT
Class Class 10
Subject English Literature
Chapter Chapter 6
Chapter Name Virtually True
Category NCERT Solutions

NCERT Solutions for Class 10 English Literature Chapter 6 Virtually True

TEXTUAL EXERCISES
(Pages 71, 78)

Question 1.
Before reading the story, attempt the following working in groups of four or five.

(a) Do you play computer games ? How many hours do you spend playing games on the computer as compared to outdoor games ?

(b) Make a list of your favourite games. Have a class discussion on the advantages and disadvantages of computer games.

(c) Look in your dictionaries/computer to find synonyms for the word ‘virtual’.

(d) Look at the K.W.L. chart given on next page. Based on the information you have gathered till now, complete the K and W columns. You may work with your partner. After reading the story complete the third column.

K-What
I know
W-What
I want to know
L-What
I learnt
Virtual Reality (a) (b) (c)
Virtual Environment (d) (e) (f)
3-D/three-dimensional (g) (h) (i)
Simulation games (j) (k) (l)
Computer simulations (m) (n) (o)
Interactive psycho-drive games (p) (q) (r)
Teleporting (s) (t) (u)

Answer:

(a) Yes, I do play computer games. On an average, I spend almost 2-3 hours playing computer games everyday. I play outdoor games for two hours daily, r

(b) My favourite games are : Pokemon Go, Road Rash, Need For Speed, Resident Evil,Grano Tursimo, Forza, Skyrim … class discussion to take place.

Advantages : pleasure-giving, entertaining, mental exercise, growth in analytical power, knowledge, general awareness, competitive spirit etc.

Disadvantages : promotion of violence, aggression, pain in backbone, in shoulders, time wastage, detachment from and neglect of family, social relationship hampered, sedentary life style, change in thinking, hardening of sensitivity, growth of abnormal behaviour.

(c) Few synonyms of VIRTUAL are : computer generated, simulated, cybernetic and realistic.

(d) (a) I know that it is not reality per se, but reality created with the help of computer software and some database. The user feels that he is inside it and is participating in it.

(b) I need to know the names of those particular softwares which help in creating such a situation. Also, if it could really be that easy then why isn’t every game prepared in such a format ?

(c) I learnt that everything is possible. Since cost is involved, so not everyone prefers to use these softwares etc.

(d) By Virtual Environment I know that it is nearer-to-truth environment. However, it is generated only by computers and softwares for the user.

(e) I want to know how much time does it take to create such an environment. Also what are the pros and cons for it ?

(f) There are no negatives of such an environment. However, the biggest plus point of this would be that the day such a procedure is initiated, the current era wouldn’t even exist. It’s all about advanced technology. The more you use it… the better it is for mankind.

(g) 3-D is about creating some sort of special effects to an image. It is to make the user feel as if the image or the subject is actually/physically present in front of , him.

(h) I want to know if there is any difference between a 3-D and a Virtual Environment.

(i) There is perhaps a difference between both of them. On the one hand 3-D is all about creating special effects to an image or a moving subject on screen. On the other hand, ‘Virtual Environment’ is all about creating a completely different environment. In it it’s not about throwing special effects over to a particular image. Instead, it’s about giving a continuous effect to the entire programme.

(j) Simulation Games. These games are made to give the player a realistic experience. For example : There is a normal racing game which is available with just a fixed image of a car. And the car keeps moving with the help of a remote controller. On the other hand, there’s another car racing game. In it the player gets to select his choice of car with all the settings of the car and tracks. There is sound as well along with a complete “Virtual Environment’. Here, in simulation games there is more of excitement than the normal games.

(k) I want to know nothing.

(l) I learnt nothing new.

(m) By Computer Simulations I know that it is all about using those extra additional gadgets to a computer. These are like, steering wheel, a shooting gun, some extra tools and weapons to play a particular game.

(n) I want to know if it is possible to get the same experience without using all such gadgets.

(o) I learnt that it’s not possible. To get a realistic feeling of the game and to actually develop more interest into it, one must have all those extra additions to his computer. Else, it would be like any other normal game.

(p) By Interactive Psycho-drive Games I learn that these are those car racing games wherein the player gets to handle a lot of crazy stuff. For example: If he wants to win the game or a particular level, he must perform some special stunts using some cheat codes. It is to gain some additional points than won by any other player.

(q) No questions.

(r) I learnt nothing.

(s) By Teleporting I know that it means switching over from one point to another within a split second of time. For example : While playing a game if the player gets a special bonus score or if he finishes up his target then he gets a special benefit. It is of skipping a level ahead or to get transformed into something else within a split second.

(t) I want to know if it has anything to do with any kind of voice service or interaction in between the game.

(u) No, it doesn’t have anything to do with any such service or interaction.

Exercises (Page 78)

  1. According to the newspaper, what had happened to Sebastian Shultz ?
  2. ‘Dad’s nutty about computers.’ What evidence is there to support this statement
  3. In what way did the second game seem very real ? (V. Imp.)
  4. The last game has tanks, jeeps, helicopters, guns and, headings. Would you put this and the other games under ?
  5. What was Michael’s theory about how Sebastian had entered the games ? (V. Imp.)

Answer:

  1. According to newspaper, Sebastian Shultz was badly injured in a motorway accident almost six weeks back. Now after six weeks he woke up from a coma that doctors had feared might have lasted forever.
  2. He’s nutty about computers as he has a Pentium 150 Mhz processor with 256 of RAM, a 1.2 GB hard disk drive and a 16 speed CD ROM with speakers, printer and also a scanner.
  3. It looked real as it was a continuation game after the first game ‘Wildwest.’ Also the name of the player was as well the same “Sebastian”.
  4. This game with machine guns, bombs, helicopter, sniper fire, tanks, can be put under the heading ‘Wargames’.
  5. Michael believed that Sebastian was also another intelligent personality like him in this world. He was so much crazy about playing games on computers. Both of them were playing a real game but virtually all together.

B. Reference to context

Read these lines from the story, then answer the questions.

‘That was my idea’ said Sebastian excitedly. ‘If only it would go a bit faster.’

  1. Where was Sebastian when he spoke these words ?
  2. What was his idea, and what was he referring to ?
  3. Was the idea a good one, and did it eventually succeed ? How ?

Answer:

  1. He was on the roof with the narrator and was waiting for the helicopter.
  2. His idea was to make it to the staircase and move upwards to get the helicopter after its landing on the roof and escape.
  3. The idea proved out to be negative as they somehow made it to the roof. But they couldn’t escape using the helicopter. They had to face almost 12 guards there along with their dogs. Sebastian got scared and he slipped down from the roof.

Question 2.
Answer the following questions briefly.
(a) Why did the news of the ‘miracle recovery’ shock Michael ?
Or
Why did the news about Sebastian Shultz shock Michael ? (CBSE 2015)

(b) Michael’s meeting with Sebastian Shultz had been a chance meeting. Where had it taken place and how ? (V. Imp.)
Or
How and where did Michael meet Sebastian Shultz ? (CBSE 2016)

(c) What kind of computers fascinated Michael and his dad ? Why ?

(d) Describe the first place where Michael was virtually transported.

(e) What help did Sebastian Shultz ask Michael for ? How did he convey this message ? (V. Imp.)
Or
How did Sebastian Shultz request Michael to help him ? (CBSE 2015)

(f) Why did Michael fail in rescuing Sebastian Shultz the first time ?
Or
Why couldn’t Michael help Sebastian the first time ? (CBSE 2015)

(g) The second attempt to rescue Sebastian Shultz too was disastrous. Give reasons. (V. Imp.)

(h) Narrate the accident that injured Sebastian Shultz.

(i) How had Sebastian Shultz entered the games ?

(j) How was Sebastian Shultz’s memory stored on Michael’s disk ? How did Michael discover that ? (V. Imp.)

Answer:

(a) Michael was shocked after reading the article as the name of the person involved in the article was Sebastian Shultz. He was someone whom Michael had recently ‘met’. Secondly, it was also because it was Sebastian with whom he had been playing all those games till then.

(b) Both of them played virtual video games on the computer screen. They thus met each other while playing virtual games on their respective computers.

(c) They were fascinated with the computers which could do almost everything from painting, playing music, creating displays etc. Both of them were very fond of playing games and doing all usual stuff on computers.

(d) The first place that Michael was virtually transported to was a complete dusty track through the centre of a town. He had a sheriffs badge pinned to his shirt.

(e) Michael received a printout from Sebastian saying that he was stuck. He wanted him to retrieve him by playing DRAGONQUEST. And he made a request for it through the computer. Precisely, it came through the computer printout.

(f) Michael was unable to save him the first time as both of them were trying to escape on a horse. However, ‘Sebastian’ was shot dead by the other ‘enemies’ running after them on their horses.

(g) The second attempt was negative as well, as he went down the dungeons with his sword drawn. But all of a sudden there appeared the dragon at the end of the corridor. He tried using his sword to kill the dragon. But it didn’t do any good and he was ‘killed.’

(h) It happened almost six weeks ago that Sebastian was badly injured in a motorway accident. His condition on arrival at the General Hospital was declared as critical, though stable. He was unable to regain his consciousness and his parents were informed that he was in a coma.

(i) Like Michael, even Sebastian was an intelligent person. He was very fond of computers and also playing games on them. This is how Sebastian entered the gaming world through playing psycho-drive video games.

(j) Michael used to play games on computers which had the capability to save the entire game in its memory while playing it. Based on this fact Sebastian’s memory had also got saved in his computer. Michael’s dad always used to tell him that a computer memory can never forget anything. Also no kind of data can get lost from it.

Michael discovered this after recollecting his father’s remarks. He also recollected Shultz’s mother stating that they stocked some games. But someone stole the lot. Shultz didn’t know what had happened to them. But Michael found them in the Computer Fair.

Question 3.
Sebastian Shultz had a close brush with death. After he recovers, he returns to school and narrates his experience to his classmates. As Sebastian Shultz, narrate your experience.
Answer:
Hi everyone ! I know you all must have been wondering about my whereabouts since so long. For all of you it’s been six weeks but for me it feels like as if everything just happened yesterday. I couldn’t even imagine that I would have to ever encounter such a situation. You may be amazed to know what had actually happened to me. Well! almost six weeks back I was on my way home riding a motorbike. All of a sudden there were these two speeding trucks which somehow hit each other and they collided. It took a split second for the two trucks to crash then and there themselves. I was riding my motorbike a little faster. On top of that the trucks were almost fifteen steps in front of me itself. In order to save myself from the crash I applied the brakes. The bike slipped and I fell over a huge pile of rocks on the pavement. I got hurt on my head and fell unconscious. It’s been almost six weeks that I’ve been hospitalized as I was in a coma. The doctors feared that it could last forever. However, by the grace of God I woke up from the coma and am fine now after having been saved by Michael, my friend. I am standing in front of you all narrating the most scariest experience of my life.

Thank you very much for a patient hearing.

Question 4.
Continue the story.

Will Michael and Sebastian Shultz meet in real life ? Will they be friends ? Will they try to re-enter the virtual world together ? You may use the following hints :

  • How the accident occurred
  • Transfer of memory
  • Meeting with Michael
  • Appeals for help
  • Rescue and recovery

Answer:

No, it’s impossible that both of them would ever meet each other. After all, it’s just a game which has got no connection with the real world.

Perhaps, they can even be good friends to each other but only virtually and electronically. In reality there is no such real person by the name of Sebastian who is playing this game with Michael. They can never enter the virtual world together as Sebastian is simply the name of a player in the game and Michael is a real human being.

They would never be able to meet each other except in this virtual world created by these gizmos only.

If we go as per the points given above we may relate the story like this : The accident occurred which led Sebastian to slip in a coma. He had played the video game through 3-D and had got stored in the memory of his computer. It had been stolen and ended at the Computer Fair. From there Michael with his father had got the interactive psycho¬drive video game which had earlier been with Sebastian.

Appeals were sent for saving Sebastian from the coma. Michael got this information from the newspaper article. He played the video game himself and got hooked with Sebastian Shultz, the character in the video game. Thus he was rescued and saved.

Question 5.
Put the following sentences in a sequential order to complete the story.

(a) Sebastian Shultz was badly injured in a motorway accident and went into a coma.
(b) Sebastian’s memory was saved in the computer when he banged his head on it during the accident.
(c) When Michael played the game, he entered Sebastian’s memory.
(d) Michael bought the latest psycho-drive games from the Computer Fair.
(e) Sebastian Shultz was the second sheriff in the ‘Dragonquest’.
(f) Michael pulled Sebastian into the helicopter and the screen flashed a score of 40,000,000.
(g) Sebastian requested Michael to try ‘Jailbreak’.
(h) Sebastian failed to save the boy who fell through the air.
(i) Sebastian thought the helicopter was the right idea and they should go into the ‘Warzone’.
(j) The games were stolen from Shultz’s house.
(k) Sebastian thanks Michael for saving his life and asks him to keep the games.

Answer:

The sequential order to complete the story is : a, b, j, d, c, e, h, i, g, f, k

WRITING TASK
Question 6.
Do you think it is a true story ? Could it happen to you one day ? Here are some opinions about computer games in general.

NCERT Solutions for Class 10 English Literature Chapter 6 Virtually True 1

Answer:

Yes, I do believe that it’s a true story, as such a thing can happen with almost anyone in this world. A similar instance could happen with me as well if I would ever think of playing games on computers like Michael did. But it all depends if I play interactive psycho-drive video games and have all the accessories needed.

Question 7.
Do you think these opinions are biased ? Write an article entitled ‘Virtual games are a reality’.
Answer:
Yes, I think these opinions are biased.

Virtual Games are a Reality

It’s a fact that virtual games are a reality. They are computer simulated environments that can simulate physical presence in places in the real world as well as in the imaginary world. It’s just a matter of a few gadgets that are required to create such an environment while playing games on computers. Hi surround speakers, digital crystal clear sound output, a 3-D screen and few other hand-led devices are all it takes to view a picture image on a computer screen or an LCD/LED. Virtual games provide players a completely different experience compared to the kind of experience they get while playing normal games. It is because one gets almost physically involved in them through 3-D and becomes an integral part of what is seen on the screen. They are far much ahead of those normal animated games which are simple and have only a limited excitement. However, one needs both time and a lot of money to indulge in such activities because these modern gadgets are very costly.

Question 8.
In groups of four, design a new computer game.
Decide on the

  • Setting
  • Plot
  • Characters
  • Objectives

Answer:
For self-attempt at class level.

LISTENING TASK
Question 9.
Listen carefully to a text on ‘Tour of Body’ and answer the questions that are given below.

On the basis of your listening to the passage complete the following statements by choosing the answers from the given options :

1. The Cave-Automatic Virtual Environment is

(a) a modern surgical procedure
(b) a three-dimensional virtual reality room
(c) an accurate projection of the eye and the brain
(d) a technique for developing anatomical pictures

2. Projected image on the four walls of a room enables researchers to

(a) carry out micro surgery
(b) understand the functioning of the brain
(c) virtually get inside the molecular structure of cells and parts of human body
(d) reconstruct damaged parts of human body

3. The ‘CAVE’ is a boon to surgeons because

(a) they can treat diseases located in unreachable parts of the human body
(b) it has made X-ray and MRI unnecessary
(c) it helps them avoid surgical procedures in most cases
(d) it enables surgeons to use very small surgical instruments

4. For the CAVE to develop a virtual environment it is essential

(a) to apply mathematical formulae
(b) to project three-dimensional images on the walls
(c) to obtain two-dimensional MRI data first
(d) to understand the nature of the diseased cells and parts

5. Once inside a three-dimensional representation of an anatomical structure, surgeons can

(a) ‘move’ through and ‘peel away’ its layers
(b) shrink themselves and travel inside the body parts
(c) convert the data into a flat picture for detailed study
(d) locate the diseased parts of the body quickly

6. Dr. Szilard Kiss used CAVE to

(a) travel inside the eye of his patient
(b) identify the scar tissue growing over the retina
(c) go inside the layers of the retina
(d) isolate the ridge of the scar tissue

Answer:

  1. → (h) a three-dimensional virtual reality room
  2. → (c) virtually get inside the molecular structure of cells and parts of human body
  3. → (a) they can treat diseases located in unreachable parts of the human body
  4. → (a) to apply mathematical formulae
  5. → (a) ‘move’ through and ‘peel away’ its layers
  6. → (c) go inside the layers of the retina.

We hope the NCERT Solutions for Class 10 English Literature Chapter 6 Virtually True help you. If you have any query regarding NCERT Solutions for Class 10 English Literature Chapter 6 Virtually True, drop a comment below and we will get back to you at the earliest.

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NCERT Solutions for Class 12 Physics Chapter 6

NCERT Solutions for Class 12 Physics Chapter 6
   

NCERT Solutions for Class 12 Physics Chapter 6 Electromagnetic Induction is important for the students of CBSE, UP, MP, Gujarat Boards. NCERT physics class 12 chapter 6 Solutions PDF is presented here to aid students grasp the Electromagnetic Induction concepts in an interesting way. All Chapter 6 Electromagnetic Induction Exercise Questions and answers help 12th standard candidates to revise the entire syllabus & secure high.

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Class 12 Physics NCERT Solutions Chapter 6 Electromagnetic Induction

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Class 12
Subject Physics
Book Physics
Chapter Number 6
Chapter Name Electromagnetic Induction

NCERT Solved Questions & Exercises for Class 12 Physics Chapter 6

Class 12 Physics NCERT Solved Questions & Exercises of Ch 6 will increase your subject knowledge by offering the strong basics on Electromagnetic Induction. All the answers provided for each question will raise your confidence to solve any questions in the actual examination. 12th Class NCERT Physics Solutions of Chapter 6 is a valuable resource for students during their homework & assignments too.

Question 1.
Predict the direction of induced current in the situations described by the following Fig. 2(a) to (f).
NCERT Solutions for Class 12 physics Chapter 6
NCERT Solutions for Class 12 physics Chapter 6.1
Answer:
(a) According to Lenz’s law south pole forms at q and north pole a to p. Therefore, induced current is from p to q.
(b) South pole develops at end q and at end x of the two coils as per Lenz’s law. Therefore, induced current is from q to p in coil PQ and x to y in coil
(c) The induced current should flow clockwise in the right loop (when seen from left) to oppose the current in the left loop. Hence, induced current flows along yzx
(d) When rheostat is adjusted to increase the current, magnetic flux through the neighbouring coil increases. As per Lenz’s law, induced current in the neighbouring coil should produce magnetic flux in opposite direction to oppose the original magnetic flux. Hence, induced current flows along
(e) When circuit breaks, magnetic flux decreases. The induced current should flow along xry to increase the magnetic flux.
(f) The magnetic flux threading the coil in the perpendicular direction is zero. Any change in current will not change this magnetic flux. Hence, no induced current is set up in the coil.

Question 2.
Use Lenz’s law to determine the direction of induced current in the situations described by Figure :
(a)
 A wire of irregular shape turning into a circular shape;
(b) A circular loop being deformed into a narrow straight wire.
NCERT Solutions for Class 12 physics Chapter 6.2
NCERT Solutions for Class 12 physics Chapter 6.3
Answer:
(a) The flux linked with the loop increases in this case so flux produced by the induced current should decrease it i.e. the direction of induced current should produce magnetic field in a direction outwards the plane of the paper. The direction of current as per right hand thumb rule comes out to be along adcba. (i.e. anti­clockwise)

(b) In this case, the flux linked with the loop is decreasing so the direction of induced current is anticlockwise so as to oppose the decrease in flux. Thus, direction of induced current is along a’d’c’b’.

Question 3.
A long solenoid with 15 turns per cm has a small loop of area 2.0 cm2 placed inside the solenoid normal to its axis. If the current carried by the solenoid changes steadily from 2.0 A to 4.0 A in 0.1s, what is the induced e.m.f. in the loop while the current is
changing ?
Answer:
byjus class 12 physics Chapter 6.4

Question 4.

A rectangular wire loop of sides 8 cm and 2 cm with a small cut ¡s moving out of a region of uniform magnetic field of magnitude O.3 T directed normal to the mop. What ¡s the e.m.f. developed across the cut if the velocity of the loop is 1 cm s-2 in a direction normal to the (a) longer side,
(b) shorter side of the loop ? For how long does the induced voltage last in each case ?
Answer:
e = B
NCERT Solutions for Class 12 physics Chapter 6.5
Question 5.
A 1.0 m long metallic rod is rotated with an angular frequency of 400 rad s_1 about an axis normal to the rod passing through its one end. The other end of the rod is in contact with a circular metallic ring. A constant and uniform magnetic Field of 0.5 T parallel to the axis exists everywhere. Calculate the e.m.f. developed between the center and the ring.
Answer:
NCERT Solutions for Class 12 physics Chapter 6.6
Question 6.
A circular coil of radius 8.0 cm and 20 turns rotates about its vertical diameter with an angular speed of 500 rad s_1 a uniform horizontal magentic field of magnitude 3.0 x 10-2 T. Obtain the maximum and average emf induced in the coil. If the coil forms a closed loop of resistance 10 Ω, calculate the maximum value of current in the coil. Calculate the average power loss due to Joule heating. Where does this power come from ?
Answer:
byjus class 12 physics Chapter 6.7
(v) Source of power loss is the external rotor which provides the necessary torque to rotate the coil.

Question 7.
A horizontal straight wire 10 m long extending from east to west is falling with a speed of 5.0 ms-1, at right angles to the horizontal component of the earth’s magnetic field,
0.30 x 10-4 Wb m-2.
(a) What is the instantaneous value of the e.m.f. induced in the wire ?
(b) What is the direction of the e.m.f. ?
(c) Which end of the wire is at the higher electrical potential ?
Answer:
NCERT Solutions for Class 12 physics Chapter 6.8
(b) Using Fleming’s Right hand rule, the direction of induced e.m.f. is from West to East.
(c) Since the rod will act as a source, the Western end will be at higher electrical potential.

Question 8.
Current in a circuit falls from 5.0 A to 0.0 As. If an average emf of 200 V is induced, give an estimate of the self-inductance of the circuit.
Answer:
NCERT Solutions for Class 12 physics Chapter 6.9

byjus class 12 physics Chapter 6.10
Question 9.

A pair of adjacent coils has a mutual inductance of 1.5 H. If the current in one coil changes from 0 to 20 A in 0.5 s, what is the change of flux linkage with the other coil ?
Answer:
Using dΦ = Mdl, we get
dΦ= 1.5 X (20 – 0) = 30 Wb

Question 10.
A jet plane is travelling towards west at a speed of 1800 km/h. What is the voltage difference developed between the ends of the wing having a span of 25 m, if the Earth’s
magnetic field at the location has a magnitude of 5 x 10-4 T and the dip angle is 30°? Answer:
NCERT Solutions for Class 12 physics Chapter 6.12

Question 11.
Suppose the loop in Exercise 6.4 is stationary but the current feeding the electromagnet
that produces the magnetic field is gradually reduced so that the field decreases from its initial value of 0.3 T at the rate of 0.02 T s-1. If the cut is joined and the loop has a resistance of 1.6 Ω, how much power is dissipated by the loop as heat ? What is the source of this power ?
Answer:
NCERT Solutions for Class 12 physics Chapter 6.13
Source of this power is the external agency which brings change in magnetic field.

Question 12.
A square loop of side 12 cm with its sides parallel to X and Y axes is moved with a velocity of 8 cm s_1 in the positive x-direction in an environment containing a magnetic field in the positive z-direction. The field is neither uniform in space nor constant in time. It has a gradient of 10-3 T cm-1 along the negative x- direction (that is it increases by
10-3 T cm-1 as one moves in the negative x-direction), and it is decreasing in time at the rate of 10-3 T s_1. Determine the direction and magnitude of the induced current in the loop if its resistance is 4.50 mΩ.
Answer:
byjus class 12 physics Chapter 6.14
NCERT Solutions for Class 12 physics Chapter 6.15
Direction of induced current is such that it increase the magnetic flux linking with the loop in positive 2-direction.

Question 13.
It is desired to measure the magnitude of field between the poles of a powerful loud speaker magnet. A small flat search coil of area 2 cm2 with 25 closely wound turns, is positioned normal to the field direction, and then quickly snatched out of the field region. Equivalently, one can give it a quick 90° turn to bring its plane parallel to the field direction. The total charge flown in the coil (measured by a ballistic galvanometer connected to coil) is 7.5 mC. The combined resistance of the coil and the galvanometer is 0.50 Ω. Estimate the field strength of magnet.
Answer:
NCERT Solutions for Class 12 physics Chapter 6.16
Question 14.
Figure shows a metal rod PQ resting on the rails AB and positioned between the poles of a permanent magnet. The rails, the rod, and the magnetic field are in three mutual perpendicular directions. A galvanometer G connects the rails through a switch K. Length of the rod = 15 cm, B = 0.50 T, resistance of the closed loop containing the rod = 9.0 mΩ. Assume the field to be uniform.
NCERT Solutions for Class 12 physics Chapter 6.17
(a) Suppose K is open and the rod is moved with a speed of 12 cm s-1 in the direction shown. Give the polarity and magnitude of the induced emf.
(b) Is there an excess charge built up at the ends of the rods when K is open ? What if K is closed ?
(c) With K open and the rod moving uniformly, there is no net force on the electrons in the rod PQ even though they do experience magnetic force due to the motion of the rod. Explain.
(d) What is the retarding force on the rod when K is closed ?
(e) How much power is required (by an external agent) to keep the rod moving at the same speed (= 12 cm s_1) when K is closed ? How much power is required when K is open ?
(f) How much power is dissipated as heat in the closed circuit ? What is the source of this power ?
(g) What is the induced emf in the moving rod if the magnetic field is parallel to the rails instead of being perpendicular ?
Answer:
(a) Using e = Bυl, we get
e = 0.5 x 12 x 10.2 x 15 x 102
= 9 x 10-3 V
The electrons in the rod will experience force along PQ, so end P becomes positive and Q becomes negative.
(b) On closing the key K, the number of electrons become more at end Q. Therefore, excess charge is maintained by the continuous current.
(c) Magnetic force gets cancelled by electric force due to excess charges of opposite sign at the ends of the rod.
(d) Retarding force, F = BIl =B eR l
byjus class 12 physics Chapter 6.18

Question 15.
An air-cored solenoid with length 30 cm, area of cross-section 25 cm2 and number of turns 500, carries a current of 2.5 A. The current is suddenly switched off in a brief time of 10-3 s. How much is the average back emf induced across the ends of the open switch in the circuit ? Ignore the variation in magnetic field near the ends of the solenoid.
Answer:
NCERT Solutions for Class 12 physics Chapter 6.28

Question 16.
(a) Obtain an expression for the mutual inductance between a long straight wire and a square loop of side a as shown in Figure
NCERT Solutions for Class 12 physics Chapter 6.29
(b) Now assume that the straight wire carries a current of 50 A and the loop is moved to the right with a constant velocity, υ = 10 m/s. Calculate the induced e.m.f. in the loop at the instant when x = 0.2 m. Take a = 0.1 m and assume that the loop has a large resistance.
Answer:
(a) Consider a small portion of the coil of thickness dt at a distance t from the current carrying wire.Then the magnetic field strength experienced by this portion
NCERT Solutions for Class 12 physics Chapter 6.30

NCERT Solutions for Class 12 physics Chapter 6.31NCERT Solutions for Class 12 physics Chapter 6.32

Question 17.

A line charge X per unit length is lodged uniformly onto the rim of a wheel of mass M and radius R. The wheel has light non-conducting spokes and is free to rotate without friction about its axis (Figure.) A uniform magnetic field extends over a circular region within the rim. It is given by
byjus class 12 physics Chapter 6.24
What is the angular velocity of the wheel after the field is suddenly switched off ?
NCERT Solutions for Class 12 physics Chapter 6.25
Answer:
Change in magnetic field is given by,
NCERT Solutions for Class 12 physics Chapter 6.26
NCERT Solutions for Class 12 physics Chapter 6.27

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NCERT Solutions for Class 12 Physics Chapter 5 Magnetism And Matter

NCERT Solutions for Class 12 Physics Chapter 5
   

NCERT Solutions for Class 12 Physics Chapter 5 Magnetism And Matter provides all needed topics and subtopics questions and answers in a detailed way for a better understanding of the concept. Thus, aims students score high in their board exams and competitive exams. Candidates who are pursuing class 12 can practice these NCERT Physics Solutions of Chapter 4 Magnetism and matter from this page for free.

Have a thorough subject knowledge from the solutions provided here and solve all types of problems and theoretical questions in the final exams with ease. For more practice, students can make use of some extra preparation resources like NCERT intext, exercises at the end of chapter 5 questions. You can download this helpful & needed NCERT Class 12 Physics Solutions for Ch 5 Magnetism and Matter PDF from here & access it in online & offline modes.

Class 12 Physics NCERT Solutions Chapter 5 Magnetism And Matter

In Chapter 5, Students of Plus Two will deal with the concept of Physics called Magnetism And Matter. The previous concept magnetism expands to the fullest in this 5th chapter Magnetism And Matter. The topics covered in this NCERT Physics chapter Magnetism And Matter are Gauss’s law & magnetism, a bar magnet & earth’s Magnetism. A total of 7 topics are included that discuss the several materials’ magnetic properties & magnetic field lines properties.

Check out the CBSE NCERT Solutions of Class 12 Physics Ch 5 Magnetism and Matter Exercises in PDF format, and score high in the board exam and competitive examination like JEE, NEET, etc.

Class 12
Subject Physics
Book Physics
Chapter Number 5
Chapter Name Magnetism And Matter

NCERT Solutions for Class 12th Physics Ch 5 Magnetism and Matter – Solved Exercises

Chapter 5 Magnetism And Matter NCERT Class 12 Physics Questions and Solutions are explained by subject experts and it is arranged based on CBSE Syllabus and NCERT guidelines. However, these NCERT Exercise Questions and answers of Class 12 Physics Chapter 5 Magnetism And Matter are most helpful to the students for their Homeworks and Assignments also.

Question 1.
Answer the following questions regarding earth’s magnetism :
(a) A vector needs three quantities for its specification. Name the three independent quantities conventionally used to specify the earth’s magnetic field.
(b) The angle of dip at a location in southern India is about 18°. Would you expect a greater or smaller dip angle in Britain ?       (C.B.S.E. 1995)
(c) If you made a map of magnetic field lines at Melbourne in Australia, would the lines seem to go into the ground or come out of the ground ?
(d) In which direction would a compass free to move in the vertical plane point to, if located right on the geomagnetic north or south pole ? (C.B.S.E. 1995)
(e) The earth’s field, it is claimed, roughly approximates the field due to a dipole of
magnetic moment 8 x 1022 JT_1 located at its center. Check the order of magnitude of this number in some way.
(f) Geologists claim that besides the main magnetic N­S poles, there are several local poles on the earth’s surface oriented in different directions. How is such a thing possible at all ?
Answer:
(a)

  1. Angle of dip or magnetic inclination, δ Galvanometer resistance, G = 12 Q The galvanometer can be converted into the voltmeter of range 0 to V (here V = 18 V) by connecting a high series resistance R given by
  2. Magnetic declination, θ
  3. Horizontal component of magnetic field of earth BH.

(b) It is about 70° in Britain because it is closer to the magnetic north pole of earth.
(c) The magnetic field lines due to the magnetism of earth would seem to come out of the ground at Melbourne in Australia because this region is in the Southern hemisphere of earth where north pole of earth’s magnet lies.
(d) Compass can point in any direction because it is free to move in horizontal plane but at magnetic poles the magnetic field of earth is exactly vertical so there will be no horizontal component of the magnetic field to effect the compass.
(e) Using the formula for magnetic field on the equatorial line of a magnetic dipole i.e.
NCERT Solutions for Class 12 physics Chapter 5
This value tells the order of magnitude of magnetic field of earth.
(f) Geologists are correct to think so because it is an approximation to consider the magnetic field of earth to be a single dipole field. The magnetised mineral deposits can be treated as local dipoles on earth.

Question 2.
Answer the following questions :
(a) The earth’s magnetic field varies from point to point in space. Does it also change with time ? If so, on what time scale does it change appreciably ?
(b) The earth’s core is known to contain iron. Yet geologists do not regard this as a source of the earth’s magnetism. Why ?
(c) The charged currents in the outer conducting regions of the earth’s core are thought to be responsible for earth’s magnetism. What might be the ‘battery’ (i.e. the source of energy) to sustain these currents ?
(d) The earth may have even reversed the direction of its field several times during its history of 4 to 5 billion years. How can geologists know about the earth’s field in such distant past ?
(e) The earth’s field departs from its dipole shape substantially at large distances (greater than about 30,000 km). What agencies may be responsible for this distortion ?(f) Interstellar space has an extremely weak magnetic field of the order of 1012 T. Can such a weak field be of any significant consequence ? Explain.
Answer:
(a) Although appreciable change can take a few hundred years yet change with time is very much there.
(b) Molten iron has a temperature more than Curie temperature so it is not ferromagnetic in nature.
(c) Probably radioactivity (i.e. emission of a, P and y particles from the nuclei) present in the interior of earth is responsible for it.
(f) During solidification of some rocks, the magnetic field of earth gets weakly recorded in these rocks. Geomagnetic history of these rocks can be traced by making analysis of such rocks.
(e) Ionosphere of earth consists of charged ions. Motion of these ions causes a magnetic field which affects the magnetic field of earth at large distances from earth. The magnetic field due to ions depends upon extra terrestrial disturbances like solar wind.
(f) At very-very large distances like interstellar distances the small fields can significantly affect the charged particles like that of cosmic rays. For small distances, the deflections are not noticeable for small fields but at very large distances the deflections are significant.
NCERT Solutions for Class 12 physics Chapter 5.1
clearly small value of B gives a very large value of radius R

Question 3.
A short bar magnet placed with its axis at 30° with a uniform external magnetic field of 0.25 T experiences a torque of magnitude equal to 4.5 X 10-2 J. What is the magnitude of magnetic moment of the magnet ?
Answer:
Using τ- MB sin θ, we get
vedantu class 12 physics Chapter 5.2

Question 4.
A short bar magnet of magnetic moment m = 0.32 JT-1 is placed in a uniform magnetic field of 0.15 T. If the bar is free to rotate in the plane of the field, which orientation would correspond to its (a) stable, and (b) unstable equilibrium ? What is the potential energy of the magnet in each case ?
Answer:
NCERT Solutions for Class 12 physics Chapter 5.3

Question 5.
A closely wound solenoid of 800 turns and area of cross section 2.5 x 10-4 m2 carries a current of 3.0 A. Explain the sense in which the solenoid acts like a bar magnet. What is its associated magnetic moment ?
Answer:
Using M = NIA, we get
M = 800 x 3 x 2.5 x 10-4 = 0.60 JT-1.
The sense is determined by the direction of the current.

Question 6.
If the solenoid in Exercise 5.5 is free to turn about the vertical direction and a uniform horizontal magnetic field of 0.25 T is applied, what is the magnitude of the torque on the solenoid when its axis makes an angle of 30° with the direction of the applied field ?
Answer:
Using x = MB sin θ, we get
x = 0.6 x 0.25 x sin 30
= 0.6 x 0.25 x 12
= 0.3 x 0.25 = 0.075 Nm
= 7.5 x 10-2 Nm.

Question 7.
A bar magnet of magnetic moment 1.5 JT-1 lies aligned with the direction of a uniform magnetic field of 0.22T.
(a) What is the amount of work required by an external torque to turn the magnet so as to align its magnetic moment, (i) normal to the field direction, (ii) opposite to the field direction ?
(b) What is the torque on the magnet in cases (i) and (ii)?
Answer:
vedantu class 12 physics Chapter 5.4

Question 8.
A closely wound solenoid of 2000 turns and area of cross-section 1.6 X 10-4 m2, carrying a current of 4.0 A, is suspended through its center allowing it to turn in a horizontal plane.
(a) What is the magnetic moment associated with the solenoid ?
(b) What is the force and torque on the solenoid if a uniform horizontal magnetic field of 7.5 x 10-2 T is set up at an angle of 30° with the axis of the solenoid?
Answer:
(a) Using M = NIA, we get
M = 2000 x 4 x 1.6 x 10-4
= 1.28 Am2
Direction of M is as per sense of current using the right handed rule.
(b) Torque, x = MB sin 0
= 1.28 x 7-5 x 10-2 x sin 30°
= 4.8 x 10-2 N m
Force is zero because of uniform field.

Question 9.
A circular coil of 16 turns and radius 10 cm carrying a current of 0.75 A rests with its plane normal to an external field of magnitude 5.0 x 10-2 T. The coil is free to turn about an axis in its plane perpendicular to the field direction. When the coil is turned slightly and released, it oscillates about its stable equilibrium with a frequency of 2.0 s_1. What is the moment of inertia of the coil about its axis of rotation ?
Answer:
NCERT Solutions for Class 12 physics Chapter 5.5
NCERT Solutions for Class 12 physics Chapter 5.6

Question 10.
A magnetic needle free to rotate in a vertical plane parallel to the magnetic meridian has its north tip pointing down at 22° with the horizontal. The horizontal component of the earth’s magnetic field at the place is known to be 0.35 G. Determine the magnitude of the earth’s magnetic field at the place.
Answer:
NCERT Solutions for Class 12 physics Chapter 5.7
Question 11.
At a certain location in Africa, a compass points 12° west of the geographic north. The north tip of the magnetic needle of a dip circle placed in the plane of magnetic meridian points 60° above the horizontal. The horizontal component of the earth’s field is measured to be 0.16 G. Specify the direction and magnitude of the earth’s field at the location.
Answer:
Using BH = B cos δ, we get
NCERT Solutions for Class 12 physics Chapter 5.8

Direction of B is 12° west of geographic meridian making upward angle of 60° with horizontal.

Question 12.
A short bar magnet has a magnetic moment of 0.48 JT-1. Give the direction and magnitude of the magnetic field produced by the magnet at a distance of 10 cm from the center of the magnet on (a) the axis, (b) the equatorial lines (normal bisector) of the magnet.
Answer:
On axial line
vedantu class 12 physics Chapter 5.9

Question 13.
A short bar magnet placed in a horizontal plane has its axis aligned along the magnetic north-south direction. Null points are found on the axis of the magnet at 14 cm from the center of the magnet. The earth’s magnetic field at the place is 0.36 G and the angle of dip is zero. What is the total magnetic field on the normal bisector of the magnet at the same distance as the null-points (i.e., 14 cm) from the center of the magnet ? (At null points, Held due to a magnet is equal and opposite to the horizontal component of earth’s magnetic field.)
Answer:
Magnetic field at the equatorial line of the magnet is given
NCERT Solutions for Class 12 physics Chapter 5.10

Question 14.
If the bar magnet in Exercise 5.13 is turned around by 180°, where will the new null-points be located ?
Answer:
When magnet is turned around 180°, its south pole lies in the geographical south direction. Hence null point will lie on the equatorial line at a distance x from die center of the magnet.
NCERT Solutions for Class 12 physics Chapter 5.11

Question 15.
A short bar magnet of magnetic moment 5.25 x 10-2 JT_1 is placed with its axis perpendicular to the earth’s field direction. At what distance from the center of the magnet, the resultant field is inclined at 45° with the earth’s field on (a) its normal bisector and (b) its axis. Magnitude of the earth’s field at the place is given to be 0.42 G. Ignore the length of the magnet in comparison to the distances involved.
Answer:
Normal bisector
(a) Let resultant magnetic field of a magnet at point P makes an angle θ= 45° with the earth’s field. Therefore,
NCERT Solutions for Class 12 physics Chapter 5.26
vedantu class 12 physics Chapter 5.13
NCERT Solutions for Class 12 physics Chapter 5.14
Question 16.
Answer the following questions :
(a) Why does a paramagnetic sample display greater magnetisation (for the same magnetising field) when cooled ?               (C.B.S.E. 1991)
(b) Why is diamagnetism, in contrast, almost independent of temperature ?
(c) If a toroid uses bismuth for its core, will the field in the core be (slightly) greater or (slightly) less than when the core is empty ?
(d) Is the permeability of a ferromagnetic material independent of the magnetic field ? If not, is it more for lower or higher fields ?
(e) Magnetic field lines are always nearly normal to the surface of a ferromagnet at every point. (This fact is analogous to the static electric field lines being normal to the surface of a conductor at every point). Why ?
(f) Would the maximum possible magnetisation of a paramagnetic sample be of the same order of magnitude as the magnetisation of a ferromagnet ?
Answer:
(a) At lower temperatures, the tendency of dealignment of magnetic dipoles with magnetising field is reduced because of decrease in their random thermal motion.
(b) The induced dipole moment in a diamagnetic sample is opposite to the magnetising field irrespective of the internal thermal motion of the atoms. Thus, diamagnetism is independent of the changes in temperature.
(c) It will be slightly less because bismuth is a diamagnetic substance.
(d) Permeability of a ferromagnetic material depends on applied magnetic field. Permeabliltiy is more for lower magnetic field.
(e) When two media are considered and one of these has μ > > 1, then magnetic field lines meet normally to this medium. Proof of this fact is available from the boundary conditions of magnetic fields (strength of magnetic field B and magnetising intensity H) at the interface of two media.
(f) The maximum possible magnetisation of a paramagnetic sample would be of the same order of magnitude as the magnetisation of a ferromagnetic sample but the paramagnetic sample requires very high magnetising field which may not be practically possible.

Question 17.
Answer the following questions :
(a) Explain qualitatively on the basis of domain picture the irreversibility in the magnetisation curve of a ferromagnet.
(b) The hysteresis loop of a soft iron piece has a much smaller area than that of a carbon steel piece. If the material is to go through repeated cycles of magnetization, which piece will dissipate greater heat energy ?
(c) ‘A system displaying a hysteresis loop such as a ferromagnet is a device for storing memory.’ Explain the meaning of this statement.
(d) What kind of ferromagnetic material is used for coating magnetic tapes in a cassette player, or for budding ‘memory stores’ in a modern computer ?
(e) A certain region of space is to be shielded from magnetic fields. Suggest a method.
Answer:
(a) It can be observed from the given curve that magnetisation persists even when the external field is removed. This reflects the irreversibility of a ferromagnet.
(b) Heat dissipated per second is directly proportional to the area of the hysteresis loop so carbon steel piece will dissipate greater heat energy.
(c) Magnetisation of a ferromagnet depends upon the applied field as number of cycles of magnetisation given to it. Thus the value of magnetisation can indicate the number of cycles of magnetisation a sample has undergone or in other words the memory with respect to the cycles stands stored in the sample.
(d) Ceramics are used for this purpose. Ferrites which are specially treated barium iron oxides are commonly used.
(e) The space to be shielded is enclosed by soft iron rings. The magnetic field lines remain confined in the ferromagnetic material of the rings and the enclosed space will be free from magnetic effect.
Note. Magnetic shielding is not as effective as electrostatic shielding is.

Question 18.
A long straight horizontal cable carries a current of 2.5 A in the direction 10° south of west to 10° north of east. The magnetic meridian of the place happens to be 10° west of the geographic meridian. The earth’s magnetic field at the location is 0.33 G, and the angle of dip is zero. Locate the line of neutral points (Ignore the thickness of the cable). (At neutral points, magnetic field due to a current-carrying cable is equal and opposite to the horizontal component of earth’s magnetic field.)
Answer:
Let neutral point lies at a distance x from the cable. Now, at neutral point, magnetic field due to cable is equal in magnitude and opposite in direction of the earth’s magnetic field.
NCERT Solutions for Class 12 physics Chapter 5.15

Question 19.
A telephone cable at a place has four long straight horizontal wires carrying a current of 1.0 A in the same direction east to west. The earth’s magnetic field at the place is 0.39 G, and the angle of dip is 35°. The magnetic declination is nearly zero. What are the resultant magnetic fields at points 4.0 cm below the cable ?
Answer:
NCERT Solutions for Class 12 physics Chapter 5.16
NCERT Solutions for Class 12 physics Chapter 5.17

Question 20.
A compass needle free to turn in a horizontal plane is placed at the center of circular coil of 30 turns and radius 12 cm. The coil is in a vertical plane making an angle of 45° with the magnetic meridian. When the current in the coil is 0.35 A, the needle points west to east.
(a) Determine the horizontal component of the earth’s magnetic field at the location.
(b) The current in the coil is reversed, and the coil is rotated about its vertical axis by an angle of 90° in the anticlockwise sense looking from above. Predict the direction of the needle. Take the magnetic declination at the place to be zero.
Answer:
NCERT Solutions for Class 12 physics Chapter 5.33

Question 21.
A magnetic dipole is under the influence of two magnetic fields. The angle between the field directions is 60°, and one of the fields has a magnitude of 1.2 x 10-2 T. If the dipole comes to stable equilibrium at an angle of 15° with this field, what is the magnitude of the other field ?
Answer:
Here B, = 1.2 X 10-2 T,θ1= 15°, θ2 = 45°.
vedantu class 12 physics Chapter 5.19
The dipole will be in equilibrium, if torque acting on dipole due to B1 is equal and opposite to the torque acting on dipole due to B2.
That is, MBsin = MB2 sin θ2
NCERT Solutions for Class 12 physics Chapter 5.20

Question 22.
A monoenergetic (18 keV) electron beam intially in the horizontal direction is subjected to a horizontal magnetic field of 0.40 G normal to the initial direction. Estimate the up
or down deflection of the beam over a distance of 30 cm (me = 9.11 x 10-19 Q.
[Note. Data in this exercise are so chosen that the answer will give you an idea of the effect of earth’s magnetic field on the motion of the electron beam from the electron gun to the screen in a TV set.]
Answer:
NCERT Solutions for Class 12 physics Chapter 5.27
NCERT Solutions for Class 12 physics Chapter 5.28

Question 23.
A sample of paramagnetic salt contains 2.0 x 1024 atomic dipoles each of dipole moment 1.5 x 10-23 JT-1. The sample is placed under a homogeneous magnetic field of 0.64 T, and cooled to a temperature of 4.2 K. The degree of magnetic saturation achieved is equal to 15%. What is the total dipole moment of the sample for a magnetic field of 0.98 T and a temperature of 2.8 K ? (Assume Curie’s law).
Answer:
Magnetic dipole moment of sample,
M = 15% of M (1.5 x 10-23) (2 x 1024)
= 30 JT-1
NCERT Solutions for Class 12 physics Chapter 5.30
Question 24.
A Rowland ring of mean radius 15 cm has 3500 turns of wire wound on a ferromagnetic core of relative permeability 800. What is the magnetic field B in the core for a magnetising current of 1.2 A?
Answer:
vedantu class 12 physics Chapter 5.31

Question 25.
The magnetic moment vectors μs and μl; associated with the intrinsic spin angular momentum S and orbital angular momentum Z, respectively, of an electron are predicted by quantum theory (and verified experimentally to a high accuracy) to be given by :
μs= -(e/m)S,
μl= -(e/2m)l
Which of these relations is in accordance with the result expected classically ? Outline the derivation of the classical result.
Answer:
NCERT Solutions for Class 12 physics Chapter 5.32

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