MCQ Questions for Class 9 Maths Chapter 15 Probability with Answers
MCQs from Class 9 Maths Chapter 15 – Probability are provided here to help students prepare for their upcoming Maths exam.
MCQs from CBSE Class 9 Maths Chapter 15: Probability
1) The probability of each event, when a coin is tossed for 1000 times with frequencies: Head:455 & Tail: 545 is:
a. 0.455 & 0.545
b. 0.5 & 0.5
c. 0.45 & 0.55
d. 455 & 545
Answer/ Explanation
Answer: (a)
Explanation: Let E and F are the event of the occurrence of Head and Tail respectively.
Probability of Occurrence of Head P(E) = No. of heads/total number of trials
P(E) = 455/1000 = 0.455
Similarly,
P(F) = No. of tails/total number of trials
P(F) = 545/1000 = 0.545
2) The sum of all probabilities equal to:
a. 4
b. 1
c. 3
d. 2
Answer/ Explanation
Answer: (b)
3) The probability of each event lies between:
a. 1 & 2
b. 1 & 10
c. 0 & 1
d. 0 & 5
Answer/ Explanation
Answer: (c)
4) If P(E) = 0.44, then P(not E) will be:
a. 0.44
b. 0.55
c. 0.50
d. 0.56
Answer/ Explanation
Answer: (d)
Explanation: We know;
P(E) + P(not E) = 1
0.44 + P(not E) = 1
P(not E) = 1 – 0.44 = 0.56
5) If P(E) = 0.38, then probability of event E, not occurring is:
a. 0.62
b. 0.38
c. 0.48
d. 1
Answer/ Explanation
Answer: (a)
Explanation: P(not E) = 1 – P(E) = 1-0.38 = 0.62
6) The probability of drawing an ace card from a deck of cards is:
a. 1/52
b. 1/26
c. 4/13
d. 1/13
Answer/ Explanation
Answer: (d)
Explanation: There are 4 aces in a deck of card.
Hence, the probability of taking one ace out of 52 card = 4/52 = 1/13
7) If probability of an event to happen is 0.3 and the probability of event not happening is:
a. 0.7
b. 0.6
c. 0.5
d. None of the above
Answer/ Explanation
Answer: (a)
Explanation: Probability of a event not happening = 1 – P(E)
P(not E) = 1 – 0.3 = 0.7
8) A dice is thrown. The probability of getting 1 and 5 is:
a. ⅙
b. ⅔
c. ⅓
d. ½
Answer/ Explanation
Answer: (c)
Explanation: The probability of getting 1 and 5 = 2/6 = ⅓
9) A batsman hits boundaries for 6 times out of 30 balls. Find the probability that he did not hit the boundaries.
a. ⅕
b. ⅖
c. ⅗
d. ⅘
Answer/ Explanation
Answer: (d)
Explanation: No. of boundaries = 6
No. of balls = 30
No. of balls without boundaries = 30 – 6 =24
Probability of no boundary = 24/30 = ⅘
10. Three coins were tossed 200 times. The number of times 2 heads came up is 72. Then the probability of 2 heads coming up is:
a. 1/25
b. 2/25
c. 7/25
d. 9/25
Answer/ Explanation
Answer: (d)
Explanation: Probability = 72/200 = 9/25