Chemistry MCQs for Class 12 with Answers Chapter 7 The p-Block Elements

Free PDF Download of CBSE Chemistry Multiple Choice Questions for Class 12 with Answers Chapter 7 The p-Block Elements. Chemistry MCQs for Class 12 Chapter Wise with Answers PDF Download was Prepared Based on Latest Exam Pattern. Students can solve NCERT Class 12 Chemistry The p-Block Elements MCQs Pdf with Answers to know their preparation level.

The p-Block Elements Class 12 Chemistry MCQs Pdf

1. Among the following, which one is a wrong statement.
(a) PH5 and BiCl5 do not exist.
(b) pπ-dπ bonds are present in SO2
(c) SeF4 and CH4 have same shape.
(d) I3 has bent geometry.

Answer/Explanation

Answer: c
Explaination:
(c) SeF4 has see-saw shape where as CH4 is tetrahedral.


2. In which of the pair of ions, both species contain S—S bond?
Chemistry MCQs for Class 12 with Answers Chapter 7 The p-Block Elements 1

Answer/Explanation

Answer:
Explaination:
Chemistry MCQs for Class 12 with Answers Chapter 7 The p-Block Elements 7


3. Which one of the following order is correct for the bond dissociation enthalpy of halogen molecule?
(a) Br2 > I2 > F2 > Cl2
(b) F2 > Cl2 > Br2 > I2
(c) I2 > Br2 > Cl2 > F2
(d) Cl2 > Br2 > F2 > I2

Answer/Explanation

Answer: d
Explaination:
(d) In F2, therefore, inter electronic repulsion, therefore, bond dissociation enthalpy is less.


4. Which is strongest acid in the following:
(a) HClO4
(b) H2SO3
(c) H2SO4
(d) HClO3

Answer/Explanation

Answer: a
Explaination:
(a) HClO4 is strongest because ‘Cl’ has +7 oxidation state.


5. In which of the following pairs, the two species are isostructural
Chemistry MCQs for Class 12 with Answers Chapter 7 The p-Block Elements 2

Answer/Explanation

Answer: c
Explaination:
(c) Both are pyramidal.
Chemistry MCQs for Class 12 with Answers Chapter 7 The p-Block Elements 8


6. The correct order of oxidising power is
(a) HClO4 > HClO3 > HClO2 > HCIO
(b) HOCl > HClO2 > HClO3 > HClO4
(c) HClO3 > HClO4 > HClO2 > HClO
(d) HCIO2 > HOCl > HClO3 > HClO4

Answer/Explanation

Answer: b
Explaination:
(b) HOCl → HCl + [O]
It is strongest oxidising agent whereas HClO4 is weakest.


7. The correct order of acid strength is
(a) HClO4 < HClO3 < HClO2 < HClO
(b) HCIO < HClO2 < HClO3 < HClO4
(c) HClO4 < HClO < HClO2 < HClO3
(d) HClO2 < HClO3 < HClO4 < HClO

Answer/Explanation

Answer: b
Explaination:
(b) As oxidation state increases, acid strength increases.


8. Among the following which is strongest oxidising agent.
(a) Br2
(b) I2
(c) Cl2
(d) F2

Answer/Explanation

Answer: d
Explaination:
(d) F2 is best oxidising agent.


9. The correct order of bond angles in the following species is
Chemistry MCQs for Class 12 with Answers Chapter 7 The p-Block Elements 3

Answer/Explanation

Answer: b
Explaination:
(b) ClO2 < Cl2O < ClO2 is increasing order of bond angle.


10. Sulphur trioxide can be obtained by which of the following:
Chemistry MCQs for Class 12 with Answers Chapter 7 The p-Block Elements 4

Answer/Explanation

Answer:
Explaination:
Chemistry MCQs for Class 12 with Answers Chapter 7 The p-Block Elements 9


11. When Cl2 reacts with hot and cone. NaOH, the oxidation number of chlorine changes from
(a) zero to +1 and zero to +5
(b) 0 to -1 and 0 to +5
(c) zero to -1 and zero to +3
(d) 0 to +1 and 0 to -3

Answer/Explanation

Answer: b
Explaination:
(b) Cl2 has oxidation number 0, in Cl (-1) and in ClO3(+5).
3Cl2 + 6NaOH(hot and cone.) → 5NaCl + NaClO3 + 3H2O


12. Acidity of diprotic acid in aqueous solution increases in the order.
(a) H2S < H2Se < H2Te
(b) H2Se < H2S < H2Te
(c) H2Te < H2S < H2Se
(d) H2Se < H2Te < H2S

Answer/Explanation

Answer: a
Explaination:
(a) Because bond dissociation enthalpy decreases as atomic size increases.


13. Which of the following statement is incorrect?
(a) ONF is isoelectronic with NO2
(h) OF2 is an oxide of fluoride
(c) Cl2O7 is an anhydride of perchloric acid
(d) O3 molecule is bent

Answer/Explanation

Answer: b
Explaination:
(b) It is fluoride of oxygen.
∵ ‘F’ is more electronegative than O.


14. Chlorine reacts with excess of NH3 to form
(a) NH4Cl
(b) N2 + HCl
(c) N2 + NH4Cl
(d) NCl3 + HCl

Answer/Explanation

Answer: c
Explaination:
(c) 8NH3 + 3Cl2 → 6NH4Cl + N2


15. Which of the following reactions is an example of redox reaction?
(a) XeF4 + O2F2 → XeF6 + O2
(b) XeF2 + PF5 → [XeF]+ [PF6]
(c) XeF6 + H2O → XeOF4 + 2HF
(d) XeF6 + 2H2O → Xeo2F2 + 2HF

Answer/Explanation

Answer: a
Explaination:
(a) Redox reaction becaueXe(+4) is getting oxidised to Xe(+6) and 0(+l) is reduced to zero.


16. On addition of cone. H2SO4 to a chloride salt, colourless fumes are evolved but in case of iodide salt, violet flames come out. This is because [NCERT Exemplar]
(a) H2SO4 reduces HI to I2
(b) HI is of violet colour
(c) HI gets oxidised to I2
(d) HI changes to HIO3

Answer/Explanation

Answer: c
Explaination:
(c) HI gets oxidised to I2


17. Which of the following pairs of ions are isoelectronic and isostructural? [NCERT Exemplar]
Chemistry MCQs for Class 12 with Answers Chapter 7 The p-Block Elements 5

Answer/Explanation

Answer: a
Explaination:
(a) CO3 and NO3 are isoelectronic (32 electrons) and Planar.
Chemistry MCQs for Class 12 with Answers Chapter 7 The p-Block Elements 10


18. Affinity for hydrogen decreases in the group from fluorine to iodine. Which of the halogen acids should have highest bond dissociation enthalpy? [NCERT Exemplar]
(a) HF
(b) HCl
(c) HBr
(d) HI

Answer/Explanation

Answer: a
Explaination:
(a) HF has highest bond dissociation enthalpy due to smaller bond length.


19. Bond dissociation enthalpy of E—H (E = element) bonds is given below. Which of the compounds will act as strongest reducing agent? [NCERT Exemplar]
Chemistry MCQs for Class 12 with Answers Chapter 7 The p-Block Elements 6
(a) NH3
(b) PH3
(c) AsH3
(d) SbH3

Answer/Explanation

Answer: d
Explaination:
(d) SbH3 due to lowest bond dissociation enthalpy.


20. Hot cone. H2SO4 acts as moderately strong oxidising agent. It oxidises both metals and non-metals. Which of the following element is oxidised by cone. H2SO4 into two gaseous products? [NCERT Exemplar]
(a) Cu
(b) S
(c) C
(d) Zn

Answer/Explanation

Answer: c
Explaination:
(c) C + 2H2SO4(conc.) → CO2 + SO2 + 2H2O


21. H2S is more acidic than H2O because
(a) oxygen is more electronegative than sulphur.
(b) atomic number of sulphur is higher than oxygen.
(c) H — S bond dissociation energy is less as compared to H — O bond.
(d) H — O bond dissociation energy is less also compared to H — S bond.

Answer

Answer: b


22. The boiling points of hydrides of group 16 are in the order
(a) H2O > H2Te > H2S > H2Se
(b) H2O > H2S > H2Se > H2Te
(c) H2O > H2Te > H2Se > H2S
(d) None of these

Answer

Answer: b


23. In the manufacture of sulphuric acid by contact process Tyndall box is used to
(a) convert SO2 and SO3
(b) test the presence of dust particles
(c) filter dust particles
(d) remove impurities

Answer

Answer: b


24. Fluorine differs from rest of the halogens in some of its properties. This is due to
(a) its smaller size and high electronegativity.
(b) lack of d-orbitals.
(c) low bond dissociation energy.
(d) All of the these.

Answer

Answer: b


25. The set with correct order of acidity is
(a) HClO < HClO2 < HClO3 < HClO4
(b) HClO4 < HClO3 < HClO2 < HClO
(c) HClO < HClO4 < HClO3 < HClO2
(d) HClO4 < HClO2 < HClO3 < HClO

Answer

Answer: b


26. When chlorine reacts with cold and dilute solution of sodium hydroxide, it forms
(a) Cl and ClO
(b) Cl and ClO2
(c) Cl and ClO3
(d) Cl and ClO4

Answer

Answer: a


27. The formation of O2+ [PtF6] is the basis for the formation of first xenon compound. This is because
(a) O2 and Xe have different sizes.
(b) both O2 and Xe are gases.
(c) O2 and Xe have comparable electro-negativities.
(d) O2 and Xe have comparable ionisation enthalpies.

Answer

Answer: d


28. Partial hydrolysis of XeF4 gives
(a) XeO3
(b) XeOF2
(c) XeOF4
(d) XeF2

Answer

Answer: b


29. Helium is preferred to be used in balloons instead of hydrogen because it is
(a) incombustible
(b) lighter than hydrogen
(c) more abundant than hydrogen
(d) non polarizable

Answer

Answer: a


30. The increasing order of reducing power of the halogen acids is
(a) HF < HCl < HBr < HI
(b) HI < HBr < HCl < HF
(c) HBr < HCl < HF < HI
(d) HCl < HBr < HF < HI

Answer

Answer: a


Note: In the following questions two or more options may be correct. (Q 21. to Q 24)
31. Which of the following options are not in accordance with the property mentioned against them? [NCERT Exemplar]
(a) F2 > Cl2 > Br2 > I2 Oxidising power.
(b) MI > MBr > MCI > MF Ionic character of metal halide.
(c) F2 > Cl2 >Br2 > I2 Bond dissociation enthalpy.
(d) HI < HBr < HCl < HF Hydrogen-halogen bond strength.

Answer/Explanation

Answer:
Explaination:
(b) MF > MCl > HBr > MI Ionic character
(c) Cl2 > Br2 > F2 > I2


32. Which of the following statements are correct? [NCERT Exemplar]
(a) Among halogens, radius ratio between iodine and fluorine is maximum.
(b) Leaving F—F bond, all halogens have weaker X—X bond than X—X’ bond in interhalogens.
(c) Among interhalogen compounds maximum number of atoms are present in iodine fluoride.
(d) Interhalogen compounds are more reactive than halogen compounds.

Answer/Explanation

Answer:
Explaination:
(a), (c) and (d) are correct.
F2 is more reactive than interhalogen compounds.
(b) is not correct, other halogens are less reactive than interhalogen compounds


33. Which of the following statements are correct for SO2 gas? [NCERT Exemplar]
(a) It acts as bleaching agent in moist conditions.
(b) It’s molecule has linear geometry.
(c) It’s dilute solution is used as disinfectant.
(d) It can be prepared by the reaction of dilute H2S04 with metal sulphide.

Answer/Explanation

Answer:
Explaination:
(b) and (d). Its molecule is bent.
Chemistry MCQs for Class 12 with Answers Chapter 7 The p-Block Elements 11
and Na2S + H2SO4 → Na2SO4 + H2S


34. Which of the following orders are correct as per the properties mentioned against each? [NCERT Exemplar]
(a) AS2O3 < SiO2 < P2O3 < SO2 Acid strength.
(b) AsH3 < PH3 < NH3 Enthalpy of vapourisation,
(c) S < O < Cl < F More negative electron gain enthalpy.
(d) H2O > H2S > H2Se > H2Te Thermal stability.

Answer/Explanation

Answer:
Explaination:
(a) and (d) are correct (b) and (c) are wrong.
(b) PH3 <ASH3 <NH3
(c) Cl > F > S > O


35. Match the compounds given in Column I with the hybridisation and shape given in Column II and mark the correct option. [NCERT Exemplar]

Column I Column II
(A) Xe F6 (1) sp3d3 – distorted octahedral
(B) Xe O3 (2) sp3d2 – square planar
(C) Xe OF4 (3) sp3– pyramidal
(D) Xe F4 (4) sp3 d2 – square pyramidal

Code:
(a) A (1) B (3) C (4) D (2)
(b) A (1) B (2) C (4) D (3)
(c) A (4) B (3) C (1) D (2)
(d) A (4) B (1) C (2) D (3)

Answer/Explanation

Answer:
Explaination:
(a) A (1) B (3) C (4) D (2)


36. Match the items of Columns I and II and mark the correct option. [NCERT Exemplar]

Column I Column II
(A) H2SO4 (1) Highest electron gain enthalpy
(B) CCl3NO2 (2) Chalcogen
(C) Cl2 (3) Tear gas
(D) Sulphur (4) Storage batteries

Answer/ExplanationCode:
(a) A (4) B (3) C (1) D (2)
(b) A (3) B (4) C (1) D (2)
(c) A (4) B (1) C (2) D (3)
(d) A (2) B (1) C (3) D (4)

Answer:
Explaination:
(a) A (4) B (3) C (1) D (2)

Note: In the following questions a statement of assertion followed by a statement of reason is given. Choose the correct answer out of the following choices. (Q.27 to Q.29)
(a) Both assertion and reason are correct statements, and reason is the correct explanation of the assertion.
(b) Both assertion and reason are correct statements, but reason is not the correct explanation of the assertion.
(c) Assertion is correct, but reason is wrong statement.
(d) Assertion is wrong but reason is correct statement.
(e) Both assertion and reason are wrong statements.
37. Assertion: HI cannot be prepared by the reaction of KI with concentrated H2SO4.
Reason: HI has lowest H-X bond strength among halogen acids.[NCERT Exemplar]

Answer/Explanation

Answer: b
Explaination:
(b) Both assertion and reason are correct statements, but reason is not the correct explanation of the assertion. HI gets oxidised to I2 as H2SO4(conc.) is oxidising agent.


38. Assertion: Both rhombic and monoclinic sulphur exist as S8 but oxygen exists as O2.
Reason: Oxygen forms pπ – pπ multiple bond due to small size and small bond length but pπ – pπ bonding is not possible in sulphur. [NCERT Exemplar]

Answer/Explanation

Answer: a
Explaination:
(a) Both assertion and reason are correct statements, and reason is the correct explanation of the assertion.


39. Assertion: NaCl reacts with concentrated H2SO4 to give colourless fumes with pungent smell. But on adding MnO2 the fumes become greenish yellow.
Reason: Mn02 oxidises HC1 to chlorine gas which is greenish yellow. [NCERT Exemplar]

Answer/Explanation

Answer: a
Explaination:
(a) Both assertion and reason are correct statements, and reason is the correct explanation of the assertion.
NaCl + H2SO4(conc.) → NaHSO4 + HCl
4HCl + MnO2 → MnCl2 + Cl2 + 2H2O


40. The mixture of cone. HCl and anhydrous ZnCl2 is called ___________ .

Answer/Explanation

Answer:
Explaination: Lucas reagent


41. Out of H2O and H2S which has higher bond angle? ___________ .

Answer/Explanation

Answer:
Explaination: H20


42. Tin reacts with excess of chlorine gas to form ___________ .

Answer/Explanation

Answer:
Explaination: SnCl4


43. Lead sulphide is heated with air to form ___________ .

Answer/Explanation

Answer:
Explaination: PbO + SO2


44. I22 gets oxidised to ___________ by cone. HNO3.

Answer/Explanation

Answer:
Explaination: HIO3


45. Interhalogen compounds are more reactive than helogens except fluorine. [True/False]

Answer/Explanation

Answer:
Explaination: True. It is due to less effective overlapping.


46. C1F is neutral molecule isoelectronic withCIO. [True/False]

Answer/Explanation

Answer:
Explaination: True. Both have 17 + 9 = 26 electrons.


47. NaF reacts with SbF6 to form Na+ [SbF7]. [True/False]

Answer/Explanation

Answer:
Explaination:
Chemistry MCQs for Class 12 with Answers Chapter 7 The p-Block Elements 12


48. Hydrolysis of XeF6 is redox reaction. [True/False]

Answer/Explanation

Answer:
Explaination: It is false. XeF6 + 3H2O > XeO3 + 6HF.


49. Ozone is thermodynamically less stable than O2. [True/False]

Answer/Explanation

Answer:
Explaination: True


50. Oxygen does not show +4 and +6 oxidation states like sulphur. Why?

Answer/Explanation

Answer:
Explaination: It is due to the absence of vacant d-orbital in oxygen.


51. Draw the structure of 03 molecule.

Answer/Explanation

Answer:
Explaination:
Chemistry MCQs for Class 12 with Answers Chapter 7 The p-Block Elements 13
It is bent molecule.


52. Write one chemical reaction equation to show that SO2 acts as a reducing agent.

Answer/Explanation

Answer:
Explaination:
Chemistry MCQs for Class 12 with Answers Chapter 7 The p-Block Elements 14


53. State reason for the following:
Sulphur has greater tendency for catenation than oxygen. [Delhi 2013; AI2016,12; DoE]
Or
O-O bond is weaker than S-S bond, why? [Chennai 2019]

Answer/Explanation

Answer:
Explaination:
It is because of strong S—S bond than 0—0 due to greater repulsion between valence electrons of smaller atoms of oxygen than sulphur atoms.


54. Write the formulae of any two oxoacids of sulphur. [AI 2015 Allahabad & Dehradun]

Answer/Explanation

Answer:
Explaination:
H2SO4 and H2SO3.


55. Write one chemical reaction equation to show that cone. H2S04 is a strong oxidising agent.

Answer/Explanation

Answer:
Explaination:
C + 2H2SO4(conc.) CO2+ 2H2O + 2SO2


56. Fluorine does not exhibit any positive oxidation state. Why? [Delhi 2013]

Answer/Explanation

Answer:
Explaination:
It is because Fluorine is most electronegative element and best oxidising agent.


57. Despite lower value of its electron gain enthalpy with negative sign, fluorine (F2) is a stronger oxidising agent than Cl2. [Delhi 2019; AI 2012; DoE]

Answer/Explanation

Answer:
Explaination:
It is due to higher standard reduction potential of F2 which is due to low bond dissociation energy of F—F bond due to inter electronic repulsion among small size F atoms, high electron gain enthalpy and highest hydration enthalpy.


58. Although the H-bonding in hydrogen fluoride is much stronger than that in water, yet water has a much higher boiling point than hydrogen fluoride. Why? [Foreign 2012]

Answer/Explanation

Answer:
Explaination:
It is because H20 molecules form H-bonds to more extent as compared to HF molecules.


59. Give a chemical reaction involved in chlorine with saturated hydrocarbon.

Answer/Explanation

Answer:
Explaination:
Chemistry MCQs for Class 12 with Answers Chapter 7 The p-Block Elements 15


60. Explain giving a reason for the following situation:
In aqueous medium, HCl is a stronger acid than HF. [Foreign 2011]

Answer/Explanation

Answer:
Explaination:
It is because bond dissociation energy of H—Cl is lower than HF due to longer bond length.


61. Give the chemical formula of any one halic acid.

Answer/Explanation

Answer:
Explaination: H0BrO2 (Bromic acid)


62. Give a chemical reaction involved in the preparation of interhalogen compound.

Answer/Explanation

Answer:
Explaination:
Chemistry MCQs for Class 12 with Answers Chapter 7 The p-Block Elements 16


63. Which compound led to the discovery of the compounds of noble gas?

Answer/Explanation

Answer:
Explaination:
which was the first compound of noble gas.


64. Complete the following reaction:
Xe + PtF6

Answer/Explanation

Answer:
Explaination:
Xe + PtF6 → Xe+[PtF6]


65. Sulphur disappears when boiled with an aqueous solution of sodium sulphite. Why?

Answer/Explanation

Answer:
Explaination:
It is due to the formation of sodium thiosulphate which is soluble in water, therefore, sulphur disappears.
Chemistry MCQs for Class 12 with Answers Chapter 7 The p-Block Elements 17


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